private void tryConvertToNumber(Node n) {
switch (n.getType()) {
case NUMBER:
// Nothing to do
return;
case AND:
case OR:
case COMMA:
tryConvertToNumber(n.getLastChild());
return;
case HOOK:
tryConvertToNumber(n.getSecondChild());
tryConvertToNumber(n.getLastChild());
return;
case NAME:
if (!NodeUtil.isUndefined(n)) {
return;
}
break;
}
Double result = NodeUtil.getNumberValue(n, shouldUseTypes);
if (result == null) {
return;
}
double value = result;
Node replacement = NodeUtil.numberNode(value, n);
if (replacement.isEquivalentTo(n)) {
return;
}
n.getParent().replaceChild(n, replacement);
reportCodeChange();
}
/** Try to fold arithmetic binary operators */
private Node performArithmeticOp(Token opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, shouldUseTypes)
|| NodeUtil.mayBeString(right, shouldUseTypes))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little awkward here.
Double lValObj = NodeUtil.getNumberValue(left, shouldUseTypes);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right, shouldUseTypes);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case BITAND:
result = NodeUtil.toInt32(lval) & NodeUtil.toInt32(rval);
break;
case BITOR:
result = NodeUtil.toInt32(lval) | NodeUtil.toInt32(rval);
break;
case BITXOR:
result = NodeUtil.toInt32(lval) ^ NodeUtil.toInt32(rval);
break;
case ADD:
result = lval + rval;
break;
case SUB:
result = lval - rval;
break;
case MUL:
result = lval * rval;
break;
case MOD:
if (rval == 0) {
return null;
}
result = lval % rval;
break;
case DIV:
if (rval == 0) {
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if ((String.valueOf(result).length()
<= String.valueOf(lval).length() + String.valueOf(rval).length() + 1
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
&& Math.abs(result) <= MAX_FOLD_NUMBER)
|| Double.isNaN(result)
|| result == Double.POSITIVE_INFINITY
|| result == Double.NEGATIVE_INFINITY) {
return NodeUtil.numberNode(result, null);
}
return null;
}
