コード例 #1
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  @Test
  public void testEmptyContext() {
    ConsistentHashPartitionFilter filter = new ConsistentHashPartitionFilter();
    List<ServiceEndPoint> endPoints = ImmutableList.of(FOO, BAR);

    assertEquals(endPoints, filter.filter(endPoints, PartitionContextBuilder.empty()));
  }
コード例 #2
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  @Test
  public void testConsistency() {
    ConsistentHashPartitionFilter filter = new ConsistentHashPartitionFilter();
    List<ServiceEndPoint> endPoints = ImmutableList.of(FOO, BAR);

    // Generate a context to reuse and ensure consistency. What's in the context doesn't matter.
    PartitionContext context = PartitionContextBuilder.of(UUID.randomUUID().toString());

    assertEquals(filter.filter(endPoints, context), filter.filter(endPoints, context));
  }
コード例 #3
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  @Test
  public void testIrrelevantPartitionContext() {
    ConsistentHashPartitionFilter filter =
        new ConsistentHashPartitionFilter("cluster", "ensemble", "group");
    List<ServiceEndPoint> endPoints = ImmutableList.of(FOO, BAR);

    // Ignores the PartitionContext because it doesn't have an entry for cluster, ensemble or group.
    assertEquals(
        endPoints, filter.filter(endPoints, PartitionContextBuilder.of("partition", "aaa")));
  }
コード例 #4
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  @Test
  public void testHashToBar() {
    ConsistentHashPartitionFilter filter = new ConsistentHashPartitionFilter();
    List<ServiceEndPoint> endPoints = ImmutableList.of(FOO, BAR);

    // It just so happens that "c" hashes to the same place as "bar".  As long as the
    // ConsistentHashEndPointFilter
    // implementation doesn't change in a backward-compatible way, this should be deterministic and
    // testable.
    assertEquals(singleton(BAR), filter.filter(endPoints, PartitionContextBuilder.of("c")));
  }
コード例 #5
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  @Test
  public void testRelevantPartitionContext() {
    ConsistentHashPartitionFilter filter =
        new ConsistentHashPartitionFilter("cluster", "ensemble", "group");
    List<ServiceEndPoint> endPoints = ImmutableList.of(FOO, BAR);

    // Doesn't ignore the PartitionContext because it has an entry for at least one of cluster,
    // ensemble or group.
    assertEquals(
        singleton(FOO), filter.filter(endPoints, PartitionContextBuilder.of("ensemble", "aaa")));
  }
コード例 #6
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  @Test
  public void testServiceIdConflict() {
    ConsistentHashPartitionFilter filter = new ConsistentHashPartitionFilter();

    // Setup the ring with FOO and BAR.
    assertEquals(
        singleton(FOO), filter.filter(ImmutableList.of(FOO, BAR), PartitionContextBuilder.of("a")));

    // Add a new server that will get ignored because it has the same ID as FOO and FOO comes last
    // in the list.
    assertEquals(
        singleton(FOO),
        filter.filter(ImmutableList.of(FOO2, FOO, BAR), PartitionContextBuilder.of("a")));

    // Now remove the original FOO and verify that FOO2 is discovered.  This can go wrong if we're
    // not careful in
    // the ring update implementation because removing FOO doesn't change the set of end point IDs.
    assertEquals(
        singleton(FOO2),
        filter.filter(ImmutableList.of(FOO2, BAR), PartitionContextBuilder.of("a")));
  }
コード例 #7
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 @Override
 public PartitionContext forCall(Method method, Object... args) {
   return PartitionContextBuilder.empty();
 }