示例#1
0
 public int[] getContainedPositions(BoundingBox boundingBox) {
   List<Integer> result = new ArrayList<>();
   List<P> positions = getPositions();
   for (int i = 0; i < positions.size(); i++) {
     P position = positions.get(i);
     if (position.hasCoordinates() && boundingBox.contains(position)) result.add(i);
   }
   return toArray(result);
 }
示例#2
0
 public int[] getPositionsWithinDistanceToPredecessor(double distance) {
   List<Integer> result = new ArrayList<>();
   List<P> positions = getPositions();
   if (positions.size() <= 2) return new int[0];
   P previous = positions.get(0);
   for (int i = 1; i < positions.size() - 1; i++) {
     P next = positions.get(i);
     if (!next.hasCoordinates() || next.calculateDistance(previous) <= distance) result.add(i);
     else previous = next;
   }
   return toArray(result);
 }
示例#3
0
 /**
  * Removes duplicate adjacent {@link #getPositions() positions} from this route, leaving only
  * distinct neighbours
  */
 public void removeDuplicates() {
   List<P> positions = getPositions();
   P previous = null;
   int index = 0;
   while (index < positions.size()) {
     P next = positions.get(index);
     if (previous != null && (!next.hasCoordinates() || next.calculateDistance(previous) <= 0.0)) {
       positions.remove(index);
     } else index++;
     previous = next;
   }
 }