Java EntityHuman.isAlive示例

示例#1

文件： EntityBlockBreakingSkeleton.java 项目： CheeseSoftware/ZombieInvasion

  public EntityHuman findNearbyVulnerablePlayer(double d0, double d1, double d2) {
    if (world.players.size() > 0) {
      int i = r.nextInt(world.players.size());
      EntityHuman entityhuman1 = (EntityHuman) this.world.players.get(i);

      if (!entityhuman1.abilities.isInvulnerable && entityhuman1.isAlive()) {
        return entityhuman1;
      }
    }
    return null;
  }