/**
* Find the innermost enclosing shell EdgeRing containing the argument EdgeRing, if any. The
* innermost enclosing ring is the <i>smallest</i> enclosing ring. The algorithm used depends on
* the fact that: <br>
* ring A contains ring B iff envelope(ring A) contains envelope(ring B) <br>
* This routine is only safe to use if the chosen point of the hole is known to be properly
* contained in a shell (which is guaranteed to be the case if the hole does not touch its shell)
*
* @return containing EdgeRing, if there is one or null if no containing EdgeRing is found
*/
public static EdgeRing findEdgeRingContaining(EdgeRing testEr, List shellList) {
LinearRing testRing = testEr.getRing();
Envelope testEnv = testRing.getEnvelopeInternal();
Coordinate testPt = testRing.getCoordinateN(0);
EdgeRing minShell = null;
Envelope minShellEnv = null;
for (Iterator it = shellList.iterator(); it.hasNext(); ) {
EdgeRing tryShell = (EdgeRing) it.next();
LinearRing tryShellRing = tryShell.getRing();
Envelope tryShellEnv = tryShellRing.getEnvelopeInternal();
// the hole envelope cannot equal the shell envelope
// (also guards against testing rings against themselves)
if (tryShellEnv.equals(testEnv)) continue;
// hole must be contained in shell
if (!tryShellEnv.contains(testEnv)) continue;
testPt =
CoordinateArrays.ptNotInList(testRing.getCoordinates(), tryShellRing.getCoordinates());
boolean isContained = false;
if (CGAlgorithms.isPointInRing(testPt, tryShellRing.getCoordinates())) isContained = true;
// check if this new containing ring is smaller than the current minimum ring
if (isContained) {
if (minShell == null || minShellEnv.contains(tryShellEnv)) {
minShell = tryShell;
minShellEnv = minShell.getRing().getEnvelopeInternal();
}
}
}
return minShell;
}
private void findRightmostEdgeAtVertex() {
/**
* The rightmost point is an interior vertex, so it has a segment on either side of it. If these
* segments are both above or below the rightmost point, we need to determine their relative
* orientation to decide which is rightmost.
*/
Coordinate[] pts = minDe.getEdge().getCoordinates();
Assert.isTrue(
minIndex > 0 && minIndex < pts.length,
"rightmost point expected to be interior vertex of edge");
Coordinate pPrev = pts[minIndex - 1];
Coordinate pNext = pts[minIndex + 1];
int orientation = CGAlgorithms.computeOrientation(minCoord, pNext, pPrev);
boolean usePrev = false;
// both segments are below min point
if (pPrev.y < minCoord.y
&& pNext.y < minCoord.y
&& orientation == CGAlgorithms.COUNTERCLOCKWISE) {
usePrev = true;
} else if (pPrev.y > minCoord.y
&& pNext.y > minCoord.y
&& orientation == CGAlgorithms.CLOCKWISE) {
usePrev = true;
}
// if both segments are on the same side, do nothing - either is safe
// to select as a rightmost segment
if (usePrev) {
minIndex = minIndex - 1;
}
}
/**
* Tests whether this ring is a hole. Due to the way the edges in the polyongization graph are
* linked, a ring is a hole if it is oriented counter-clockwise.
*
* @return <code>true</code> if this ring is a hole
*/
public boolean isHole() {
LinearRing ring = getRing();
return CGAlgorithms.isCCW(ring.getCoordinates());
}