示例#1
1
文件: A1.java 项目: paohui817/arena
 public ListNode partition(ListNode head, int x) {
   ListNode headOfHead = new ListNode(-1);
   headOfHead.next = head;
   ListNode p = headOfHead;
   while (p.next != null) {
     p = p.next;
     // CUT begin
     debug(p.val);
     // CUT end
   }
   ListNode tail = new ListNode(-1);
   p.next = tail;
   p = headOfHead;
   ListNode q = tail;
   while (p.next != tail) {
     if (p.next.val < x) {
       p = p.next;
     } else {
       q.next = p.next;
       q = q.next;
       p.next = p.next.next;
       q.next = null;
     }
   }
   p.next = tail.next;
   return headOfHead.next;
 }
示例#2
0
文件: A1.java 项目: paohui817/arena
 public void solve(InputReader in, OutputWriter out) {
   int n = in.nextInt();
   int x = in.nextInt();
   ListNode head = new ListNode(-1);
   ListNode p = head;
   for (int i = 0; i < n; i++) {
     p.next = new ListNode(in.nextInt());
     p = p.next;
     //            out.println(p.val);
   }
   ListNode res = new A1().partition(head.next, x);
   p = res;
   while (p != null) {
     out.println(p.val);
     p = p.next;
   }
 }