Пример #1
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  /**
   * Locate the first cluster that has id equal to <code>id</code>. The search includes all the
   * clusters in the input and their sub-clusters. The first cluster with matching identifier is
   * returned or <code>null</code> if no such cluster could be found.
   */
  public static Cluster find(int id, Collection<Cluster> clusters) {
    for (Cluster c : clusters) {
      if (c != null) {
        if (c.id != null && c.id == id) {
          return c;
        }

        if (!c.getSubclusters().isEmpty()) {
          final Cluster sub = find(id, c.getSubclusters());
          if (sub != null) {
            return sub;
          }
        }
      }
    }

    return null;
  }
Пример #2
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 /*
  * Recursive descent into subclusters.
  */
 private static void flatten(ArrayList<Cluster> flattened, Collection<Cluster> clusters) {
   for (Cluster c : clusters) {
     flattened.add(c);
     final List<Cluster> subclusters = c.getSubclusters();
     if (!subclusters.isEmpty()) {
       flatten(flattened, subclusters);
     }
   }
 }
Пример #3
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  /** Replace document refids with the actual references upon deserialization. */
  private void documentIdToReference(Cluster cluster, Map<String, Document> documents) {
    if (cluster.documentIds != null) {
      for (Cluster.DocumentRefid documentRefid : cluster.documentIds) {
        cluster.addDocuments(documents.get(documentRefid.refid));
      }
    }

    for (Cluster subcluster : cluster.getSubclusters()) {
      documentIdToReference(subcluster, documents);
    }
  }
Пример #4
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  /** A recursive routine for collecting unique documents from this cluster and subclusters. */
  private static Set<Document> collectAllDocuments(Cluster cluster, Set<Document> docs) {
    if (cluster == null) {
      return docs;
    }

    docs.addAll(cluster.getDocuments());

    final List<Cluster> subclusters = cluster.getSubclusters();
    for (final Cluster subcluster : subclusters) {
      collectAllDocuments(subcluster, docs);
    }

    return docs;
  }