/**
   * Get a list of piece numbers being requested
   *
   * @return list of Long values
   */
  public int[] getRequestedPieceNumbers() {
    if (destroyed) return new int[0];

    /** Cheap hack to reduce (but not remove all) the # of duplicate entries */
    int iLastNumber = -1;
    int pos = 0;
    int[] pieceNumbers;

    try {
      lock_mon.enter();

      // allocate max size needed (we'll shrink it later)
      pieceNumbers = new int[queued_messages.size() + loading_messages.size() + requests.size()];

      for (Iterator iter = queued_messages.keySet().iterator(); iter.hasNext(); ) {
        BTPiece msg = (BTPiece) iter.next();
        if (iLastNumber != msg.getPieceNumber()) {
          iLastNumber = msg.getPieceNumber();
          pieceNumbers[pos++] = iLastNumber;
        }
      }

      for (Iterator iter = loading_messages.iterator(); iter.hasNext(); ) {
        DiskManagerReadRequest dmr = (DiskManagerReadRequest) iter.next();
        if (iLastNumber != dmr.getPieceNumber()) {
          iLastNumber = dmr.getPieceNumber();
          pieceNumbers[pos++] = iLastNumber;
        }
      }

      for (Iterator iter = requests.iterator(); iter.hasNext(); ) {
        DiskManagerReadRequest dmr = (DiskManagerReadRequest) iter.next();
        if (iLastNumber != dmr.getPieceNumber()) {
          iLastNumber = dmr.getPieceNumber();
          pieceNumbers[pos++] = iLastNumber;
        }
      }

    } finally {
      lock_mon.exit();
    }

    int[] trimmed = new int[pos];
    System.arraycopy(pieceNumbers, 0, trimmed, 0, pos);

    return trimmed;
  }
Пример #2
0
 public int getPieceNumber() {
   return piece.getPieceNumber();
 }