Пример #1
0
 public static MinMaxT convertMinMaxPair(MinMaxPair mmp) {
   return new MinMaxT(mmp.getMinValue(), mmp.getMinValue());
 }
Пример #2
0
  public static MinMaxPair getMinMax(int array[], int minIndex, int maxIndex) {
    System.out.print(
        "\n"
            + "arrayLow["
            + minIndex
            + "]: "
            + array[minIndex]
            + ", arrayHigh["
            + maxIndex
            + "]: "
            + array[maxIndex]);
    MinMaxPair result = new MinMaxPair();
    MinMaxPair leftArrayMinMax = new MinMaxPair();
    MinMaxPair rightArrayMinMax = new MinMaxPair();

    // if there is only one element
    if (minIndex == maxIndex) {
      result.max = array[minIndex];
      result.min = array[minIndex];
      return result;
    }

    // if there are two elements
    if (maxIndex == minIndex + 1) {
      if (array[minIndex] > array[maxIndex]) {
        result.max = array[minIndex];
        result.min = array[maxIndex];
        noOfComparisons++;
      } else {
        result.max = array[maxIndex];
        result.min = array[minIndex];
      }
      return result;
    }

    noOfComparisons++;
    // if there are more than 2 elements
    // ----------DIVIDE----------
    int mid = (minIndex + maxIndex) / 2;
    leftArrayMinMax = getMinMax(array, minIndex, mid);
    rightArrayMinMax = getMinMax(array, mid + 1, maxIndex);

    // ------COMBINE---------------------
    if (leftArrayMinMax.min < rightArrayMinMax.min) {
      result.min = leftArrayMinMax.min;
      noOfComparisons++;
    } else {
      result.min = rightArrayMinMax.min;
    }

    if (leftArrayMinMax.max > rightArrayMinMax.max) {
      result.max = leftArrayMinMax.max;
      noOfComparisons++;
    } else {
      result.max = rightArrayMinMax.max;
    }

    return result;
  }