Exemplo n.º 1
0
 @Override
 public int compareTo(@Nonnull final UTF8String other) {
   int len = Math.min(numBytes, other.numBytes);
   // TODO: compare 8 bytes as unsigned long
   for (int i = 0; i < len; i++) {
     // In UTF-8, the byte should be unsigned, so we should compare them as unsigned int.
     int res = (getByte(i) & 0xFF) - (other.getByte(i) & 0xFF);
     if (res != 0) {
       return res;
     }
   }
   return numBytes - other.numBytes;
 }
Exemplo n.º 2
0
  /** Returns whether this contains `substring` or not. */
  public boolean contains(final UTF8String substring) {
    if (substring.numBytes == 0) {
      return true;
    }

    byte first = substring.getByte(0);
    for (int i = 0; i <= numBytes - substring.numBytes; i++) {
      if (getByte(i) == first && matchAt(substring, i)) {
        return true;
      }
    }
    return false;
  }
Exemplo n.º 3
0
  /**
   * Levenshtein distance is a metric for measuring the distance of two strings. The distance is
   * defined by the minimum number of single-character edits (i.e. insertions, deletions or
   * substitutions) that are required to change one of the strings into the other.
   */
  public int levenshteinDistance(UTF8String other) {
    // Implementation adopted from org.apache.common.lang3.StringUtils.getLevenshteinDistance

    int n = numChars();
    int m = other.numChars();

    if (n == 0) {
      return m;
    } else if (m == 0) {
      return n;
    }

    UTF8String s, t;

    if (n <= m) {
      s = this;
      t = other;
    } else {
      s = other;
      t = this;
      int swap;
      swap = n;
      n = m;
      m = swap;
    }

    int[] p = new int[n + 1];
    int[] d = new int[n + 1];
    int[] swap;

    int i, i_bytes, j, j_bytes, num_bytes_j, cost;

    for (i = 0; i <= n; i++) {
      p[i] = i;
    }

    for (j = 0, j_bytes = 0; j < m; j_bytes += num_bytes_j, j++) {
      num_bytes_j = numBytesForFirstByte(t.getByte(j_bytes));
      d[0] = j + 1;

      for (i = 0, i_bytes = 0; i < n; i_bytes += numBytesForFirstByte(s.getByte(i_bytes)), i++) {
        if (s.getByte(i_bytes) != t.getByte(j_bytes)
            || num_bytes_j != numBytesForFirstByte(s.getByte(i_bytes))) {
          cost = 1;
        } else {
          cost =
              (ByteArrayMethods.arrayEquals(
                      t.base, t.offset + j_bytes, s.base, s.offset + i_bytes, num_bytes_j))
                  ? 0
                  : 1;
        }
        d[i + 1] = Math.min(Math.min(d[i] + 1, p[i + 1] + 1), p[i] + cost);
      }

      swap = p;
      p = d;
      d = swap;
    }

    return p[n];
  }