Exemplo n.º 1
0
 public void solve(int testNumber, InputReader in, PrintWriter out) {
   int counter = in.nextInt();
   int maxm = 0;
   int mw = 0;
   int maxw = 0;
   int wm = 0;
   for (int i = 0; i < counter; ++i) {
     int M = in.nextInt();
     int W = in.nextInt();
     int S = in.nextInt();
     int m = Math.min(M, S);
     int w = Math.min(W, Math.max(0, S - m));
     maxm += m;
     mw += w;
     w = Math.min(W, S);
     m = Math.min(M, Math.max(0, S - w));
     maxw += w;
     wm += m;
   }
   if (maxm <= mw) {
     out.println(maxm);
   } else if (maxw <= wm) {
     out.println(maxw);
   } else {
     out.println(Math.min((maxm + mw) / 2, (maxw + wm) / 2));
   }
 }
Exemplo n.º 2
0
 public void solve(final int testNumber, final InputReader in, final PrintWriter out) {
   int counter = in.nextInt();
   double[] max = in.nextDoubleArray(counter);
   double[] min = in.nextDoubleArray(counter);
   double[] smin = new double[counter + 1];
   double[] smax = new double[counter + 1];
   for (int i = 1; i <= counter; ++i) {
     smin[i] = smin[i - 1] + min[i - 1];
     smax[i] = smax[i - 1] + max[i - 1];
   }
   double[] p = new double[counter + 1];
   p[0] = 0;
   for (int i = 1; i <= counter; ++i) {
     double B = (smin[i] + smax[i]);
     double C = smax[i];
     double D = B * B - 4 * C;
     p[i] = (B + Math.sqrt(D)) / 2.0;
   }
   for (int i = counter - 1; i > 0; --i) {
     p[i + 1] -= p[i];
     if (p[i + 1] < 1e-9) p[i + 1] = 0;
   }
   for (int i = 1; i <= counter; ++i) {
     out.print(p[i] + " ");
   }
   out.println();
   for (int i = 1; i <= counter; ++i) {
     out.print((min[i - 1] + max[i - 1] - p[i]) + " ");
   }
 }
Exemplo n.º 3
0
 public void solve(int testNumber, InputReader in, PrintWriter out) {
   int blocks = in.nextInt();
   Block[] list = new Block[blocks];
   for (int i = 0; i < blocks; ++i) {
     list[i] = new Block(in.next(), i);
   }
   Arrays.sort(list);
   int sum = 0;
   for (int i = 0; i < blocks; ++i) {
     sum += list[i].balance;
     if (sum < 0) {
       out.println("NO");
       return;
     }
   }
   if (sum != 0) {
     out.println("NO");
   } else {
     out.println("YES");
     for (Block block : list) {
       out.print(block.idx + 1);
       out.print(' ');
     }
     out.println();
   }
 }
Exemplo n.º 4
0
 public void solve(int testNumber, InputReader in, PrintWriter out) {
   int length = in.nextInt();
   int alphabetSize = in.nextInt();
   int[] string = new int[length + 1];
   for (int i = 0; i < length; ++i) {
     string[i] = in.nextInt();
   }
   int[] suffixArray = StringUtils.buildSuffixArray(string);
   int[] lcp = StringUtils.buildLCP(string, suffixArray);
   int[] stack = new int[lcp.length];
   int top = 0;
   int bestPosition = -1;
   int bestLength = -1;
   for (int i = 0; i < lcp.length; ++i) {
     while (top > 0 && lcp[stack[top - 1]] >= lcp[i]) {
       int current = stack[top - 1];
       int previous = top == 1 ? -1 : stack[top - 2];
       int currentLength = i - previous;
       if (bestPosition == -1
           || (long) lcp[bestPosition] * bestLength < (long) lcp[current] * currentLength) {
         bestPosition = current;
         bestLength = currentLength;
       }
       top--;
     }
     stack[top++] = i;
   }
   if ((long) lcp[bestPosition] * bestLength < length) {
     out.println(length);
     out.println(length);
     for (int i = 0; i < length; ++i) {
       if (i > 0) out.print(' ');
       out.print(string[i]);
     }
   } else {
     out.println((long) lcp[bestPosition] * bestLength);
     out.println(lcp[bestPosition]);
     for (int i = 0; i < lcp[bestPosition]; ++i) {
       if (i > 0) out.print(' ');
       out.print(string[suffixArray[bestPosition] + i]);
     }
   }
 }
Exemplo n.º 5
0
 public void solve(int testNumber, InputReader in, PrintWriter out) {
   int initial = in.nextInt();
   int min, max;
   min = max = initial;
   for (int i = 0; i < Integer.toString(initial).length(); ++i) {
     for (int j = 0; j < i; ++j) {
       assert initial >= powers[i];
       int a = initial / powers[i] % 10;
       int b = initial / powers[j] % 10;
       if (i == Integer.toString(initial).length() - 1 && b == 0) continue;
       int tmp = initial + (b - a) * powers[i] + (a - b) * powers[j];
       min = Math.min(min, tmp);
       max = Math.max(max, tmp);
     }
   }
   out.printf("Case #%d: %d %d\n", testNumber, min, max);
 }
Exemplo n.º 6
0
 public void solve(final int testNumber, final InputReader in, final PrintWriter out) {
   long a = in.nextLong() % MODULO;
   long b = in.nextLong() % MODULO;
   int n = in.nextInt();
   //        long a = 1_000_000_000_000_000_000L % MODULO;
   //        long b = 1_000_000_000_010_000_000L % MODULO;
   //        int n = 10_000_000;
   MagicQueue queue = new MagicQueue(n);
   for (int i = 0; i < n; ++i) {
     queue.push((int) ((a + i) % MODULO));
   }
   long answer = queue.getProduct();
   for (int cur = (int) a; cur != b; cur = (cur + 1) % MODULO) {
     queue.pop();
     queue.push(cur + n);
     answer += queue.getProduct();
   }
   out.println(answer % MODULO);
 }