public static double rint(double x) {
// Floating point has a mantissa with an accuracy of 52 bits so
// any number bigger than 2^52 is effectively a finite integer value.
// This case also filters out NaN and infinite values.
if (NativeMath.abs(x) < (double) (1L << 52)) {
double mod2 = x % 2;
if ((mod2 == -1.5) || (mod2 == 0.5)) {
x = NativeMath.floor(x);
} else {
x = NativeMath.round(x);
}
}
return x;
}
public static double floor(double x) {
return NativeMath.floor(x);
}
