/** 人名消歧,比如.邓颖超生前->邓颖 超生 前 fix to 丁颖超 生 前! 规则的方式增加如果两个人名之间连接是- ， ·，•则连接 */
public static void nameAmbiguity(Term[] terms) {
Term from = null;
Term term = null;
Term next = null;
for (int i = 0; i < terms.length - 1; i++) {
term = terms[i];
if (term != null && term.termNatures() == TermNatures.NR && term.getName().length() == 2) {
next = terms[i + 2];
if (next.termNatures().personAttr.split > 0) {
term.setName(term.getName() + next.getName().charAt(0));
terms[i + 2] = null;
terms[i + 3] = new Term(next.getName().substring(1), next.getOffe(), TermNatures.NW);
TermUtil.termLink(term, terms[i + 3]);
TermUtil.termLink(terms[i + 3], next.to());
}
}
}
// 外国人名修正
for (int i = 0; i < terms.length; i++) {
term = terms[i];
if (term != null
&& term.getName().length() == 1
&& i > 0
&& WordAlert.CharCover(term.getName().charAt(0)) == '·') {
from = term.from();
next = term.to();
if (from.natrue().natureStr.startsWith("nr") && next.natrue().natureStr.startsWith("nr")) {
from.setName(from.getName() + term.getName() + next.getName());
TermUtil.termLink(from, next.to());
terms[i] = null;
terms[i + 1] = null;
}
}
}
}
/**
* 数字+数字合并,zheng
*
* @param terms
*/
public static void recognition(Term[] terms) {
int length = terms.length - 1;
Term from = null;
Term to = null;
Term temp = null;
for (int i = 0; i < length; i++) {
if (terms[i] == null) {
continue;
} else if (".".equals(terms[i].getName())) {
// 如果是.前后都为数字进行特殊处理
to = terms[i].getTo();
from = terms[i].getFrom();
if (from.getTermNatures().numAttr.flag && to.getTermNatures().numAttr.flag) {
from.setName(from.getName() + "." + to.getName());
TermUtil.termLink(from, to.getTo());
terms[to.getOffe()] = null;
terms[i] = null;
i = from.getOffe() - 1;
}
continue;
} else if (!terms[i].getTermNatures().numAttr.flag) {
continue;
}
temp = terms[i];
// 将所有的数字合并
while ((temp = temp.getTo()).getTermNatures().numAttr.flag) {
terms[i].setName(terms[i].getName() + temp.getName());
}
// 如果是数字结尾
if (temp.getTermNatures().numAttr.numEndFreq > 0) {
terms[i].setName(terms[i].getName() + temp.getName());
temp = temp.getTo();
}
// 如果不等,说明terms[i]发生了改变
if (terms[i].getTo() != temp) {
TermUtil.termLink(terms[i], temp);
// 将中间无用元素设置为null
for (int j = i + 1; j < temp.getOffe(); j++) {
terms[j] = null;
}
i = temp.getOffe() - 1;
}
}
}