コード例 #1
0
ファイル: ClientController.java プロジェクト: piopawlu/ols
  /**
   * Removes the given exporter from the list of exporters.
   *
   * @param aExporter the exporter to remove, cannot be <code>null</code>.
   */
  public void removeExporter(final Exporter aExporter) {
    if (this.mainFrame != null) {
      this.mainFrame.removeExportMenuItem(aExporter.getName());
    }

    updateActions();
  }
コード例 #2
0
ファイル: ClientController.java プロジェクト: piopawlu/ols
  /**
   * Returns the names of all current available exporters.
   *
   * @return an array of exporter names, never <code>null</code>, but can be empty.
   */
  public String[] getExporterNames() {
    try {
      final ServiceReference[] serviceRefs =
          this.bundleContext.getAllServiceReferences(Exporter.class.getName(), null);
      final int count = serviceRefs == null ? 0 : serviceRefs.length;

      final String[] result = new String[count];

      for (int i = 0; i < count; i++) {
        final Exporter exporter = (Exporter) this.bundleContext.getService(serviceRefs[i]);

        result[i] = exporter.getName();
        this.bundleContext.ungetService(serviceRefs[i]);
      }

      return result;
    } catch (InvalidSyntaxException exception) {
      throw new RuntimeException("getAllExporterNames failed!", exception);
    }
  }
コード例 #3
0
ファイル: ClientController.java プロジェクト: piopawlu/ols
  /**
   * Returns the exporter with the given name.
   *
   * @param aName the name of the exporter to return, cannot be <code>null</code>.
   * @return the exporter with the given name, can be <code>null</code> if no such exporter is
   *     found.
   * @throws IllegalArgumentException in case the given name was <code>null</code> or empty.
   */
  public Exporter getExporter(final String aName) throws IllegalArgumentException {
    if ((aName == null) || aName.trim().isEmpty()) {
      throw new IllegalArgumentException("Name cannot be null or empty!");
    }

    try {
      final ServiceReference[] serviceRefs =
          this.bundleContext.getAllServiceReferences(Exporter.class.getName(), null);
      final int count = (serviceRefs == null) ? 0 : serviceRefs.length;

      for (int i = 0; i < count; i++) {
        final Exporter exporter = (Exporter) this.bundleContext.getService(serviceRefs[i]);

        if (aName.equals(exporter.getName())) {
          return exporter;
        }
      }

      return null;
    } catch (InvalidSyntaxException exception) {
      throw new RuntimeException("getExporter failed!", exception);
    }
  }
コード例 #4
0
ファイル: ClientController.java プロジェクト: piopawlu/ols
 /**
  * Exports the current diagram to the given exporter.
  *
  * @param aExporter the exporter to export to, cannot be <code>null</code>.
  * @param aOutputStream the output stream to write the export to, cannot be <code>null</code>.
  * @throws IOException in case of I/O problems.
  */
 public void exportTo(final Exporter aExporter, final OutputStream aOutputStream)
     throws IOException {
   if (this.mainFrame != null) {
     aExporter.export(this.dataContainer, this.mainFrame.getDiagramScrollPane(), aOutputStream);
   }
 }