コード例 #1
0
ファイル: LineSegment.java プロジェクト: ChrisXin/ECE-155
  /**
   * Returns true iff the line segments overlap; weaker than <code>theSame</code>.
   *
   * @param other
   * @return true iff this and other overlap
   */
  public boolean isOverlapping(LineSegment other) {
    if (!VectorUtils.areEqual(m, other.m) && !VectorUtils.areEqual(b, other.b)) return false;

    // same line, now check for overlap---
    // the start point of one should be inside the other
    return containsPoint(other.start) || other.containsPoint(start);
  }
コード例 #2
0
ファイル: LineSegment.java プロジェクト: ChrisXin/ECE-155
  /**
   * Return the point where this LineSegment intersects another line segment.
   *
   * @param other the other line segment.
   * @return the point where the two segments intersect, or null if they do not.
   */
  public PointF findIntercept(LineSegment other) {
    // Special case for vertical lines
    if (Float.isInfinite(m) && Float.isInfinite(other.m)) {
      if (start.x == other.start.x)
        return new PointF(Float.POSITIVE_INFINITY, Float.POSITIVE_INFINITY);
      return null;
    }
    // special case for horizontal lines
    if (m == 0 && other.m == 0) {
      if (start.y == other.start.y)
        return new PointF(Float.POSITIVE_INFINITY, Float.POSITIVE_INFINITY);
      return null;
    }

    float x, y;

    if (Float.isInfinite(other.m)) {
      x = other.start.x;
    } else if (Float.isInfinite(m)) {
      return other.findIntercept(this);
    } else {
      // first find intercept.
      // solve for X
      // m1x + b1 = m2x + b2
      // b1 - b2 = (m2 - m1)x

      x = (b - other.b) / (other.m - m);
    }

    // Now solve for y
    y = m * x + b;

    // now see if this point is on both line segments.
    if (isPointInSegment(x, y) && other.isPointInSegment(x, y)) {
      return new PointF(x, y);
    }

    return null;
  }