public boolean isMatch(String s, String p) {
// without this optimization, it will fail for large data set
int plenNoStar = 0;
for (char c : p.toCharArray()) if (c != '*') plenNoStar++;
if (plenNoStar > s.length()) return false;
s = " " + s;
p = " " + p;
int slen = s.length();
int plen = p.length();
boolean[] dp = new boolean[slen]; // 记录0的状态，一共len+1个
TreeSet<Integer> firstTrueSet = new TreeSet<Integer>();
firstTrueSet.add(0);
dp[0] = true;
boolean allStar = true;
for (int pi = 1; pi < plen; pi++) {
if (p.charAt(pi) != '*') allStar = false;
for (int si = slen - 1; si >= 0; si--) {
if (si == 0) {
dp[si] = allStar ? true : false;
} else if (p.charAt(pi) != '*') {
if (s.charAt(si) == p.charAt(pi) || p.charAt(pi) == '?') dp[si] = dp[si - 1];
else dp[si] = false;
} else {
int firstTruePos = firstTrueSet.isEmpty() ? Integer.MAX_VALUE : firstTrueSet.first();
if (si >= firstTruePos) dp[si] = true;
else dp[si] = false;
}
if (dp[si]) firstTrueSet.add(si);
else firstTrueSet.remove(si);
}
}
return dp[slen - 1];
}
private void merge(Interval p, Interval n) {
if (p != null && n != null && (p.end == n.start || p.end + 1 == n.start)) {
p.end = n.end;
set.remove(n);
}
}
