コード例 #1
0
 /**
  * The main program.
  *
  * @param args command line arguments (ignored)
  */
 public static void main(String args[]) {
   AAA aAAA = new AAA();
   AA aAA = (AA) aAAA;
   A aA = (A) aAA;
   /*
    * Casting the object doesn't change the nature of the object. It only
    * tells the compiler to treat 'aA' as if it was a class AA object and
    * 'aAA' as if it was a class AAA object . But 'aA' remains to be an
    * object of the class A and 'aAA' remains to be an object of the class
    * AA. Hence, 'aA.intPlusPlus', 'aAA.intPlusPlus()' incremented the
    * instance variable 'aInt' of the class AAA by 1 and value of 'aInt'
    * for the classes A and AA remains untampered (i.e. 11).
    */
   aAAA.intPlusPlus();
   aAA.intPlusPlus();
   aA.intPlusPlus();
   /*
    * Note: If we specify a toString() method inside Class AAA, then it
    * would print 14 for "SOP(aA), SOP(aAA), SOP(aAAA)". That means,
    * control passes to the toString() method of the class A, wherein, the
    * value of 'aInt' was defined as 11. Hence, we can conclude that if a
    * class doesn't have a toString() method, it goes back to the
    * superclass for object representation and the "this" reference changes
    * to an instance of the superclass (i.e this.aInt will be 11, which is
    * the value that it got from the superclass AA's constructor).
    */
   System.out.println("aA:        " + aA);
   System.out.println("aAA:       " + aAA);
   /*
    * For the statement below, the value printed on the console is the
    * value of the instance variable 'aInt' of the object of class AA as
    * class AAA does not have a 'toString()' method. Hence, the control
    * passes to the superclass of class AAA (i.e class AA) and, though, the
    * name of the class is printed as 'AAA', the value of the instance
    * variable 'aInt' is that for the object of the class AA (i.e. 11).
    */
   System.out.println("aAAA:      " + aAAA);
   /*
    * By casting, the compiler was told to treat the objects 'aA' and 'aAA'
    * as if it were the objects of the class AAA. The instance variable
    * 'aInt' of the class AAA was incremented thrice since its method
    * 'intPlusPlus' was called three times. Therefore, the final value in
    * 'aInt' was 14
    */
   System.out.println("aAAA:.aInt " + aAAA.aInt);
 }
コード例 #2
0
 public void display(int indent) {
   super.display(indent);
   AA.display(indent + 1);
 }
コード例 #3
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 @Test
 public void convertRowCoordinateToExcelRowForExtendedAlphabet() {
   assertThat(AA.ordinal(), is(26));
   assertThat(ZZ.ordinal(), is(701));
 }
コード例 #4
0
ファイル: StaticTest.java プロジェクト: xiecs/my
 /** @param args */
 public static void main(String[] args) {
   AA.aa();
 }
コード例 #5
0
ファイル: A.java プロジェクト: sxenos/eclipse.jdt.core
 void m() {
   a.f = 0; /*1*/
   b.f = 0; /*2*/
   ab.f = 0; /*3*/
 }