Esempio n. 1
0
  @Override
  public <T> Path.Entry<T> get(ID eid, Content.Type<T> ct) throws IOException {
    updateContents();

    ID tid = id.append(eid.get(0));

    int idx = binarySearch(contents, nentries, tid);
    if (idx >= 0) {
      // At this point, we've found a matching index for the given ID.
      // However, there maybe multiple matching IDs with different
      // content types. Therefore, we need to check them all to see if
      // they match the requested entry.
      Path.Item item = contents[idx];
      do {
        if (item instanceof Entry && eid.size() == 1) {
          // In this case, we're looking for and have found an exact
          // item.
          Entry entry = (Entry) item;
          if (entry.contentType() == ct) {
            return entry;
          }
        } else if (item instanceof Path.Folder && eid.size() > 1) {
          // In this case, the ID is indicates the item is not
          // contained in this folder.
          Path.Folder folder = (Path.Folder) item;
          return folder.get(eid.subpath(1, eid.size()), ct);
        }
      } while (++idx < nentries && (item = contents[idx]).id().equals(tid));
    }

    // no dice
    return null;
  }
Esempio n. 2
0
  @Override
  public boolean contains(Path.Entry<?> e) throws IOException {
    updateContents();
    Path.ID eid = e.id();
    boolean contained;

    if (id == eid.parent()) {
      // The requested entry is contained in this folder. Therefore, we
      // need to search for it.
      contained = true;
    } else if (id == eid.subpath(0, id.size())) {
      // This folder is a parent of the requested entry. Therefore, we
      // need to looking for a matching folder entry. If we find one, then
      // we ask it for the requested entry.
      eid = eid.subpath(0, id.size() + 1);
      contained = false;
    } else {
      return false;
    }

    int idx = binarySearch(contents, nentries, eid);
    if (idx >= 0) {
      // At this point, we've found a matching index for the given ID.
      // However, there maybe multiple matching IDs (e.g. with different
      // content types). Therefore, we need to check them all to see if
      // they match the requested entry.
      Path.Item item = contents[idx];
      do {
        if (item == e) {
          return true;
        } else if (!contained && item instanceof Path.Folder) {
          Path.Folder folder = (Path.Folder) item;
          return folder.contains(e);
        }
      } while (++idx < nentries && (item = contents[idx]).id().equals(eid));
    }

    // no dice
    return false;
  }
Esempio n. 3
0
  @Override
  public <T> void getAll(Content.Filter<T> filter, Set<Path.ID> entries) throws IOException {
    updateContents();

    // It would be nice to further optimise this loop. The key issue is that,
    // at some point, we might know the filter could never match. In which
    // case, we want to stop the recursion early, rather than exploring a
    // potentially largel subtree.

    for (int i = 0; i != nentries; ++i) {
      Path.Item item = contents[i];
      if (item instanceof Entry) {
        Entry entry = (Entry) item;
        if (filter.matches(entry.id(), entry.contentType())) {
          entries.add(entry.id());
        }
      } else if (item instanceof Path.Folder && filter.matchesSubpath(item.id())) {
        Path.Folder folder = (Path.Folder) item;
        folder.getAll(filter, entries);
      }
    }
  }
Esempio n. 4
0
  @Override
  public List<Entry<?>> getAll() throws IOException {
    ArrayList entries = new ArrayList();
    updateContents();

    // It would be nice to further optimise this loop. Basically, to avoid
    // creating so many ArrayList objects. However, it's tricky to get right
    // given Java's generic type system.

    for (int i = 0; i != nentries; ++i) {
      Path.Item item = contents[i];
      if (item instanceof Entry) {
        Entry entry = (Entry) item;
        entries.add(entry);
      } else if (item instanceof Path.Folder) {
        Path.Folder folder = (Path.Folder) item;
        entries.addAll(folder.getAll());
      }
    }

    return entries;
  }