/** * 将包含拖码的list与胆码进行组合, * * @param list 包含拖码的list * @param intDanmaAry 胆码数组 * @param playTypeLen 玩法的长度,如任选3:长度为3 * @return 胆码与拖码合并进行排列 */ private String combDanTuo(List<int[]> list, int[] intDanmaAry, int playTypeLen) { String result = ""; int danmaAryLen = intDanmaAry.length; // 整理结果 for (int i = 0; i < list.size(); i++) { int[] t = (int[]) list.get(i); // 将胆码与拖码进行合并,合并成新的数组 int[] combNewAry = new int[t.length + danmaAryLen]; for (int k = 0; k < t.length; k++) { combNewAry[k] = t[k]; } int tempCount = 0; for (int k = t.length; k < combNewAry.length; k++) { combNewAry[k] = intDanmaAry[tempCount++]; } // tempAry[tempAry.length-1] = Integer.parseInt(danma); // 对新数组进行从小到大排序 JStringToolkit.intOrder(combNewAry, 1); // 对结果进行组合即可,在计算时,将开奖结果按照相应的顺序进行组合即可 String tempStr = ""; for (int temp : combNewAry) { if (tempStr.equals("")) { tempStr = String.valueOf(temp); } else { tempStr = tempStr + "," + temp; } } if (result.equals("")) { result = result + tempStr; } else { result = result + "|" + tempStr; } /* String temp = ""; //应该先见所有的胆码与拖码分别进行组合后,再将组合后的值分别进行排列 //如果是任选2并且是组选前2胆拖,则进行重新计算如果是任选2并且是组选前2胆拖,则进行重新计算 List<String> tList = new ArrayList<String>(); pailie.permutation(tList,combNewAry, playTypeLen,"1"); for(String ss : tList){ if (result.equals("")) { result = result + ss; } else { result = result + "|" + ss; } } */ } return result; }