private String readTypeName(Buffer buffer) {
   int len = buffer.readInt();
   if (buffer.remaining() <= len) {
     throw new IllegalArgumentException(
         "Incomplete buffer. Must contain "
             + len
             + " bytes, "
             + "but only "
             + buffer.remaining()
             + " were found.");
   }
   byte[] bytes = new byte[len];
   buffer.read(bytes);
   return new String(bytes);
 }
Esempio n. 2
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    private boolean tryEmit(Buffer buffer) {

      IN next;

      Iterator<Buffer.View> views = codec.iterateDecode(buffer, decoderContext);

      if (!views.hasNext()) {
        combine(buffer);
        return false;
      }

      Buffer.View cursor;

      while (views.hasNext()) {
        cursor = views.next();
        if (cursor != null) {
          next = codec.decodeNext(cursor.get(), decoderContext);
          if (next != null && BackpressureUtils.getAndSub(PENDING_UPDATER, this, 1L) > 0) {
            subscriber.onNext(next);
          } else {
            combine(buffer.slice(cursor.getStart(), buffer.limit()));
            return next != null;
          }
        } else {
          combine(buffer);
          return false;
        }
      }
      if (buffer.remaining() > 0) {
        combine(buffer);
        return false;
      }
      return true;
    }
Esempio n. 3
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  /**
   * Very efficient method for parsing an {@link Integer} from the given {@literal Buffer}. Much
   * faster than {@link Integer#parseInt(String)}.
   *
   * @param b The {@literal Buffer} to slice.
   * @return The int value or {@literal null} if the {@literal Buffer} could not be read.
   */
  public static Integer parseInt(Buffer b) {
    if (b.remaining() == 0) {
      return null;
    }

    b.snapshot();
    int len = b.remaining();

    int num = 0;
    int dec = 1;
    for (int i = (b.position + len); i > b.position; ) {
      char c = (char) b.buffer.get(--i);
      num += Character.getNumericValue(c) * dec;
      dec *= 10;
    }

    b.reset();

    return num;
  }
Esempio n. 4
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 /**
  * Append the given {@link Buffer} to this {@literal Buffer}.
  *
  * @param buffers The {@link Buffer Buffers} to append.
  * @return {@literal this}
  */
 public Buffer append(Buffer... buffers) {
   if (buffers == null) return this;
   for (Buffer b : buffers) {
     if (b == null) continue;
     int pos = position();
     int len = b.remaining();
     ensureCapacity(len);
     if (b.byteBuffer() != null) {
       buffer.put(b.byteBuffer());
       buffer.position(pos + len);
     }
   }
   return this;
 }
Esempio n. 5
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    @Override
    public Buffer.View next() {
      int limit = buffer.limit();
      int endchunk = canDecodeNext(buffer, context);

      if (endchunk == -1) {
        return null;
      }

      Buffer.View view = buffer.createView(buffer.position(), endchunk);

      if (buffer.remaining() > 0) {
        buffer.position(Math.min(limit, view.getEnd()));
        buffer.limit(limit);
      }
      return view;
    }
Esempio n. 6
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  /**
   * Very efficient method for parsing a {@link Long} from the given {@literal Buffer}. Much faster
   * than {@link Long#parseLong(String)}.
   *
   * @param b The {@literal Buffer} to slice.
   * @return The long value or {@literal null} if the {@literal Buffer} could not be read.
   */
  public static Long parseLong(Buffer b) {
    if (b.remaining() == 0) {
      return null;
    }
    ByteBuffer bb = b.buffer;
    int origPos = bb.position();
    int len = bb.remaining();

    long num = 0;
    int dec = 1;
    for (int i = len; i > 0; ) {
      char c = (char) bb.get(--i);
      num += Character.getNumericValue(c) * dec;
      dec *= 10;
    }

    bb.position(origPos);

    return num;
  }
Esempio n. 7
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 protected int canDecodeNext(Buffer buffer, Object context) {
   return delimiter == null
       ? (buffer.remaining() > 0 ? buffer.limit() : -1)
       : buffer.indexOf(delimiter);
 }
 @Override
 protected int canDecodeNext(Buffer buffer, Object context) {
   return buffer.remaining() > 0 ? buffer.limit() : -1;
 }