public static void main(String[] args) {
BinaryTree B1 = new BinaryTree();
B1.add(10);
B1.add(5);
B1.add(13);
B1.add(12);
B1.add(4);
B1.add(7);
B1.add(14);
B1.add(20);
B1.add(1);
B1.add(2);
System.out.println("Inorder traversal:");
B1.displayInorder(B1.root);
System.out.println("Preorder traversal:");
B1.displayPreOrder(B1.root);
System.out.println("Postorder traversal:");
B1.displayPostOrder(B1.root);
System.out.println("Level order Traversal:");
B1.displayLevelOrder();
System.out.println("Nodes at distance 2 from root:");
B1.printNodesAtDistK(B1.root, 0, 2);
B1.printVerticalOrder(B1.root);
System.out.println("LCA of 2 and 7 is " + B1.findLCA(B1.root, 2, 7).value);
System.out.println("Distance between 12 and 1 is " + B1.findDistance(12, 1));
System.out.println("\nTree after trimming:");
B1.root = B1.trimTree(B1.root, 4, 10);
B1.displayLevelOrder();
int height = B1.height(B1.root);
System.out.println("The hieght of the tree is " + height);
if (B1.ifBST(B1.root, Integer.MIN_VALUE, Integer.MAX_VALUE))
System.out.println("The tree is a Binary search tree");
else System.out.println("The tree is not a Binary search tree");
}
public static void main(String[] args) {
/**
* A B C D E F G When traversing a tree, every node should always be visited as a root of a
* tree!!! preOrder: A B C D E G F inOrder: C B E G D F A postOrder: C G E F D B A levelOrder: A
* B C D E F G
*/
BinaryTree btree = new BinaryTree();
BiNode[] nodes = new BiNode[7];
nodes[0] = new BiNode("A");
nodes[1] = new BiNode("B");
nodes[2] = new BiNode("C");
nodes[3] = new BiNode("D");
nodes[4] = new BiNode("E");
nodes[5] = new BiNode("F");
nodes[6] = new BiNode("G");
btree.root = nodes[0];
nodes[0].left = nodes[1];
nodes[1].left = nodes[2];
nodes[1].right = nodes[3];
nodes[3].left = nodes[4];
nodes[3].right = nodes[5];
nodes[4].right = nodes[6];
// operations
btree.preOrder();
btree.inOrder();
btree.postOrder();
btree.levelOrder();
}