//computes all primes up to some n and store them the queue
public void computeTo(int n)
{
// add int 2:n into queue
int i=2;
int count=0;
int value1=0;
int value2=0;
int size=0;
int whilesize=(int)Math.sqrt(n);
while(i<=n)// n=10
{
queueNumbers.enqueue(i);//2 3 4 5 6 7 8 9 10
i++;
}
do{
value1= (int)queueNumbers.dequeue(); //value1=2,
queuePrime.enqueue(value1);// 2
for (int count=0; count<queueNumbers.getsize(); count++)// 0-10
{
value2=(int)queueNumber.dequeue();// 3
if(value2%value1 !=0)//3%2 !=0
{
queueNumbers.enqueue(value2);// store 3 in queueNumbers,
}
}
}// end do
while(value2 <= whilesize)
{
size= queueNumbers.getsize();
for(int k=0; i<size; i++)
{
queueNumbers.dequeue(value2);
queuePrime.enqueue(value2);
}
}// end while
/**
create a queue and fill it with the consecutive integers 2 through n inclusive.
create an empty queue to store primes.
do {
obtain the next prime by removing the first value in the queue of numbers.
put the next prime into the queue of primes.
go through the queue of numbers, eliminating numbers divisible by the next prime.
} while (the next prime < sqrt(n))
all remaining values in numbers queue are prime, so transfer them to primes queue
*/
}
// finds the max prime number found last time computeTo was called
//cycle through the queue and grab the last element
public int getMax()
{
int max=0;
int value=0;
// say queuePrime is 2 3 5 7 11
for(int i=0; i<queuePrime.getsize(); i++)
{
value=(int)queuePrime.dequeue(i); //2 , 3, 5, 7, 11
queueMax.enqueue(value); //2, 3, 5, 7, 11
if( i= queuePrime.getsize()-1)
{
max=value;
}
}
queuePrime= queueMax;
return max;
}