Esempio n. 1
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  public Point2D projectOnAC(Point2D q) {
    Vector2D r = a.sub(c);
    Vector2D s = r.rightNormal();
    double t = ((q.sub(c)).cross(r) / (r.cross(s)));

    return q.add(s.scale(t));
  }
Esempio n. 2
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 public Triangle2D(Point2D a, Point2D b, Point2D c) {
   this.a = a;
   this.b = b;
   this.c = c;
   ab = b.sub(a);
   ac = c.sub(a);
   bc = c.sub(b);
 }
Esempio n. 3
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  public Point2D projectOnAB(Point2D q) {
    Vector2D r = a.sub(b);
    Vector2D s = r.rightNormal();
    double t = ((q.sub(b)).cross(r) / (r.cross(s)));
    //		System.out.println(t);

    return q.add(s.scale(t));
  }
Esempio n. 4
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 public Triangle2D(double xa, double ya, double xb, double yb, double xc, double yc) {
   this.a = new Point2D(xa, ya);
   this.b = new Point2D(xb, yb);
   this.c = new Point2D(xc, yc);
   ab = b.sub(a);
   ac = c.sub(a);
   bc = c.sub(b);
 }
Esempio n. 5
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  public boolean contains(Point2D p) {
    // Compute vectors
    Vector2D v0 = ac;
    Vector2D v1 = ab;
    Vector2D v2 = p.sub(a);

    // Compute dot products
    double dot00 = v0.dot(v0); // dot(v0, v0);
    double dot01 = v0.dot(v1); // dot(v0, v1);
    double dot02 = v0.dot(v2); // dot(v0, v2);
    double dot11 = v1.dot(v1); // dot(v1, v1);
    double dot12 = v1.dot(v2); // dot(v1, v2);

    // Compute barycentric coordinates
    double invDenom = 1 / (dot00 * dot11 - dot01 * dot01);
    double u = (dot11 * dot02 - dot01 * dot12) * invDenom;
    double v = (dot00 * dot12 - dot01 * dot02) * invDenom;

    // Check if point is in triangle
    return (u >= 0) && (v >= 0) && (u + v < 1);
  }