Esempio n. 1
0
  /** Skips checks for existing keys. */
  private void addResize(T key) {
    // Check for empty buckets.
    int hashCode = key.hashCode();
    int index1 = hashCode & mask;
    T key1 = keyTable[index1];
    if (key1 == null) {
      keyTable[index1] = key;
      if (size++ >= threshold) resize(capacity << 1);
      return;
    }

    int index2 = hash2(hashCode);
    T key2 = keyTable[index2];
    if (key2 == null) {
      keyTable[index2] = key;
      if (size++ >= threshold) resize(capacity << 1);
      return;
    }

    int index3 = hash3(hashCode);
    T key3 = keyTable[index3];
    if (key3 == null) {
      keyTable[index3] = key;
      if (size++ >= threshold) resize(capacity << 1);
      return;
    }

    push(key, index1, key1, index2, key2, index3, key3);
  }
Esempio n. 2
0
  /** Returns true if the key was not already in the set. */
  public boolean add(T key) {
    if (key == null) throw new IllegalArgumentException("key cannot be null.");
    T[] keyTable = this.keyTable;

    // Check for existing keys.
    int hashCode = key.hashCode();
    int index1 = hashCode & mask;
    T key1 = keyTable[index1];
    if (key.equals(key1)) return false;

    int index2 = hash2(hashCode);
    T key2 = keyTable[index2];
    if (key.equals(key2)) return false;

    int index3 = hash3(hashCode);
    T key3 = keyTable[index3];
    if (key.equals(key3)) return false;

    // Find key in the stash.
    for (int i = capacity, n = i + stashSize; i < n; i++) if (key.equals(keyTable[i])) return false;

    // Check for empty buckets.
    if (key1 == null) {
      keyTable[index1] = key;
      if (size++ >= threshold) resize(capacity << 1);
      return true;
    }

    if (key2 == null) {
      keyTable[index2] = key;
      if (size++ >= threshold) resize(capacity << 1);
      return true;
    }

    if (key3 == null) {
      keyTable[index3] = key;
      if (size++ >= threshold) resize(capacity << 1);
      return true;
    }

    push(key, index1, key1, index2, key2, index3, key3);
    return true;
  }