Esempio n. 1
0
  public Bitmap loadImage(String path) throws OutOfMemoryError {
    Bitmap bitsat;

    try {
      BitmapFactory.Options options = new BitmapFactory.Options();
      options.inPreferredConfig = Bitmap.Config.ARGB_8888;
      options.inJustDecodeBounds = true;
      Bitmap b = BitmapFactory.decodeFile(path, options);

      options.inSampleSize = Futils.calculateInSampleSize(options, px, px);

      // Decode bitmap with inSampleSize set
      options.inJustDecodeBounds = false;

      Bitmap bit;
      if (path.startsWith("smb:/")) bit = BitmapFactory.decodeStream(new SmbFileInputStream(path));
      else bit = BitmapFactory.decodeFile(path, options);

      bitsat =
          bit; // decodeFile(path);//.createScaledBitmap(bits,imageViewReference.get().getHeight(),imageViewReference.get().getWidth(),true);
    } catch (Exception e) {
      Drawable img = ContextCompat.getDrawable(mContext, R.drawable.ic_doc_image);
      Bitmap img1 = ((BitmapDrawable) img).getBitmap();
      bitsat = img1;
    }
    return bitsat;
  }
 @Override
 protected void onActivityResult(int requestCode, int resultCode, Intent intent) {
   if (requestCode == FILECHOOSER_RESULTCODE) { // found this from StackOverflow
     if (null == mUploadMessage) return;
     Uri result = intent == null || resultCode != RESULT_OK ? null : intent.getData();
     mUploadMessage.onReceiveValue(result);
     mUploadMessage = null;
   } else {
     // -----------I wrote this code below this line----------------------------------
     jpegData = intent.getExtras().getByteArray("image");
     Bitmap img = BitmapFactory.decodeByteArray(jpegData, 0, jpegData.length);
     Drawable d = new BitmapDrawable(img);
     profilePicture.setBackground(d);
   }
 }