public static BiTreeNode newNode(int data) {
BiTreeNodeData d = new BiTreeNodeData(data);
BiTreeNode t = new BiTreeNode();
t.setData(d);
t.setLeftchild(null);
t.setRightchild(null);
return t;
}
public void postOrderTraverse(BiTreeNode node) {
if (null != node) {
postOrderTraverse(node.getLeftchild());
postOrderTraverse(node.getRightchild());
if (null != node.getData()) {
node.getData().show();
}
}
}
public static void inOrderTraverse(BiTreeNode node) {
if (null != node) {
inOrderTraverse(node.getLeftchild());
if (null != node.getData()) {
node.getData().show();
}
inOrderTraverse(node.getRightchild());
}
}
public BiTreeNode preOrderCreateBiTree(String init, BiTreeNode t) {
if ("#".equalsIgnoreCase(init.substring(0, 1))) {
t = null;
} else {
BiTreeNodeData d = new BiTreeNodeData(init.substring(0, 1));
t = new BiTreeNode();
t.setData(d);
t.setLeftchild(preOrderCreateBiTree(init.substring(1), t.getLeftchild()));
t.setRightchild(preOrderCreateBiTree(init.substring(1), t.getRightchild()));
}
return t;
}
/*
Give a binary search tree and a number, inserts a new node
with the given number in the correct place in the tree.
Returns the new root pointer which the caller should
then use (the standard trick to avoid using reference
parameters).
*/
public static BiTreeNode insert(BiTreeNode node, int data) {
if (null == node) {
return newNode(data);
} else {
if (data <= node.getData().getIdata()) {
node.setLeftchild(insert(node.getLeftchild(), data));
} else {
node.setRightchild(insert(node.getRightchild(), data));
}
// return the (unchanged) node pointer
return node;
}
}
public static void testInOrderTraverse() {
BiTreeNodeData a = new BiTreeNodeData("A");
BiTreeNodeData b = new BiTreeNodeData("B");
BiTreeNodeData c = new BiTreeNodeData("C");
BiTreeNodeData d = new BiTreeNodeData("D");
BiTreeNode A = new BiTreeNode();
A.setData(a);
BiTreeNode B = new BiTreeNode();
B.setData(b);
BiTreeNode C = new BiTreeNode();
C.setData(c);
BiTreeNode D = new BiTreeNode();
D.setData(d);
A.setLeftchild(B);
A.setRightchild(C);
B.setRightchild(D);
BiTree.inOrderTraverse(A);
}
