/**
* Produces a string form of a double given the value and the numerical base to convert it to.
* There is an instance method that uses the internally stored base. This class method can be used
* by anyone anytime.
*
* @param value the number to be converted
* @param base the numerical base to use (currently 10 or 16)
* @return a String equivalent of the value rendered appropriately.
*/
public static String formatNumber(double value, int base) {
if (base == NumberDisplayBaseChooser.HEXADECIMAL) {
long lguy = Double.doubleToLongBits(value);
return Binary.intToHexString(Binary.highOrderLongToInt(lguy))
+ Binary.intToHexString(Binary.lowOrderLongToInt(lguy)).substring(2);
} else {
return Double.toString(value);
}
}
