private void dumpMetadata(String group, List<Example> examples) {
LispTree tree = LispTree.proto.newList();
tree.addChild("metadata");
tree.addChild(LispTree.proto.newList("group", group));
tree.addChild(LispTree.proto.newList("size", "" + examples.size()));
tree.print(out);
out.println();
}
/** supports chains only */
public boolean hasOpposite(Formula formula) {
LispTree tree = formula.toLispTree();
if (tree.isLeaf()) {
String fbProperty =
FreebaseInfo.isReverseProperty(tree.value) ? tree.value.substring(1) : tree.value;
return freebaseInfo.fbPropertyHasOpposite(fbProperty);
} else {
// Un-reverse everything.
String binary1 = tree.child(2).child(0).value;
binary1 = FreebaseInfo.isReverseProperty(binary1) ? binary1.substring(1) : binary1;
String binary2 = tree.child(2).child(1).child(0).value;
binary2 = FreebaseInfo.isReverseProperty(binary2) ? binary2.substring(1) : binary2;
return freebaseInfo.fbPropertyHasOpposite(binary1)
&& freebaseInfo.fbPropertyHasOpposite(binary2);
}
}
private void compileExpression(LispTree exp) {
for (int i = 1; i < exp.children.size(); ++i) {
LispTree child = exp.child(i);
int currState = numOfStates - 1;
LanguageExpToken langExpToken =
new LanguageExpToken(child.child(0).value, child.child(1).value);
if (langExpToken.repeat == RepeatType.PLUS) {
addEdge(currState, currState + 1, langExpToken);
addEdge(currState + 1, currState + 1, langExpToken);
} else if (langExpToken.repeat == RepeatType.STAR) {
addEdge(currState, currState + 1, langExpToken);
addEdge(currState + 1, currState + 1, langExpToken);
// deal with previous edges
Map<LanguageExpToken, Set<Integer>> prevEdges =
incomingEdges[currState]; // could be NULL - for efficiency I allow this
if (prevEdges != null) {
for (LanguageExpToken prevToken : prevEdges.keySet()) {
for (Integer prevState : prevEdges.get(prevToken)) {
addEdge(prevState, currState + 1, prevToken);
}
}
}
// deal with start state
if (startStates.contains(currState)) startStates.add(currState + 1);
} else if (langExpToken.repeat == RepeatType.Q_MARK) {
addEdge(currState, currState + 1, langExpToken);
// deal with previous edges
Map<LanguageExpToken, Set<Integer>> prevEdges =
incomingEdges[currState]; // could be NULL - for efficiency I allow this
if (prevEdges != null) {
for (LanguageExpToken prevToken : prevEdges.keySet()) {
for (Integer prevState : prevEdges.get(prevToken)) {
addEdge(prevState, currState + 1, prevToken);
}
}
}
// deal with start state
if (startStates.contains(currState)) startStates.add(currState + 1);
} else addEdge(currState, currState + 1, langExpToken);
numOfStates++;
}
}
public Formula equivalentFormula(LispTree tree) {
if (tree.isLeaf()) {
boolean rev = FreebaseInfo.isReverseProperty(tree.value);
String fbProperty = rev ? tree.value.substring(1) : tree.value;
String oppositeProperty = freebaseInfo.getOppositeFbProperty(fbProperty);
return rev
? Formulas.newNameFormula(oppositeProperty)
: Formulas.newNameFormula("!" + oppositeProperty);
} else {
String binary1 = tree.child(2).child(0).value;
binary1 = FreebaseInfo.isReverseProperty(binary1) ? binary1.substring(1) : binary1;
String binary2 = tree.child(2).child(1).child(0).value;
binary2 = FreebaseInfo.isReverseProperty(binary2) ? binary2.substring(1) : binary2;
String oppositeBinary1 = freebaseInfo.getOppositeFbProperty(binary1);
String oppositeBinary2 = freebaseInfo.getOppositeFbProperty(binary2);
boolean rev = FreebaseInfo.isReverseProperty(tree.child(2).child(0).value);
return buildLambdaFormula(oppositeBinary1, oppositeBinary2, !rev);
}
}
private void dumpExample(LispTree tree) {
out.println("(example");
for (LispTree subtree : tree.children.subList(1, tree.children.size())) {
if (!subtree.isLeaf() && "derivations".equals(subtree.children.get(0).value)) {
if (subtree.children.size() == 1) {
out.println(" (derivations)");
} else {
out.println(" (derivations");
for (LispTree derivation : subtree.children.subList(1, subtree.children.size())) {
out.write(" ");
derivation.print(Integer.MAX_VALUE, Integer.MAX_VALUE, out);
out.write("\n");
}
out.println(" )");
}
} else {
out.write(" ");
subtree.print(Integer.MAX_VALUE, Integer.MAX_VALUE, out);
out.write("\n");
}
}
out.println(")");
}
/**
* Language item is defined to contain just a single language expression token
*
* @return
*/
public LanguageExpToken getLangExpToken() {
return new LanguageExpToken(
expressionTree.child(1).child(0).value, expressionTree.child(1).child(1).value);
}
public String toString() {
return expressionTree.toString();
}
/** supports chains only */
public boolean isReversed(Formula formula) {
LispTree tree = formula.toLispTree();
if (tree.isLeaf()) return FreebaseInfo.isReverseProperty(tree.value);
else return FreebaseInfo.isReverseProperty(tree.child(2).child(0).value);
}
public LispTree toLispTree() {
LispTree tree = LispTree.proto.newList();
tree.addChild("string");
tree.addChild(value);
return tree;
}
public StringValue(LispTree tree) {
this.value = tree.child(1).value;
}
private LispTree exampleToLispTree(ParserState state) {
LispTree tree = LispTree.proto.newList();
tree.addChild("example");
// Basic information
Example ex = state.ex;
if (ex.id != null) tree.addChild(LispTree.proto.newList("id", ex.id));
if (ex.utterance != null) tree.addChild(LispTree.proto.newList("utterance", ex.utterance));
if (ex.targetFormula != null)
tree.addChild(LispTree.proto.newList("targetFormula", ex.targetFormula.toLispTree()));
if (ex.targetValue != null)
tree.addChild(LispTree.proto.newList("targetValue", ex.targetValue.toLispTree()));
if (ex.context != null) tree.addChild(ex.context.toLispTree());
// Language info
if (ex.languageInfo != null) {
if (ex.languageInfo.tokens != null)
tree.addChild(
LispTree.proto.newList("tokens", LispTree.proto.newList(ex.languageInfo.tokens)));
if (ex.languageInfo.lemmaTokens != null)
tree.addChild(
LispTree.proto.newList(
"lemmaTokens", LispTree.proto.newList(ex.languageInfo.lemmaTokens)));
if (ex.languageInfo.posTags != null)
tree.addChild(
LispTree.proto.newList("posTags", LispTree.proto.newList(ex.languageInfo.posTags)));
if (ex.languageInfo.nerTags != null)
tree.addChild(
LispTree.proto.newList("nerTags", LispTree.proto.newList(ex.languageInfo.nerTags)));
if (ex.languageInfo.nerValues != null)
tree.addChild(
LispTree.proto.newList("nerValues", LispTree.proto.newList(ex.languageInfo.nerValues)));
}
// Derivations
LispTree derivations = LispTree.proto.newList();
derivations.addChild("derivations");
List<Derivation> preds = state.predDerivations;
for (int i = 0; i < preds.size(); i++) {
Derivation deriv = preds.get(i);
if (!isPruned(deriv)) {
derivations.addChild(deriv.toLispTree());
}
}
tree.addChild(derivations);
return tree;
}
