/**
* Unsubscribe the given subscription id.
*
* @see #subscribe(Map, Entity, Sensor, SensorEventListener)
*/
public synchronized boolean unsubscribe(SubscriptionHandle sh) {
if (!(sh instanceof Subscription))
throw new IllegalArgumentException(
"Only subscription handles of type Subscription supported: sh="
+ sh
+ "; type="
+ (sh != null ? sh.getClass().getCanonicalName() : null));
Subscription s = (Subscription) sh;
boolean b1 = allSubscriptions.remove(s.id) != null;
boolean b2 =
LanguageUtils.removeFromMapOfCollections(
subscriptionsByToken, makeEntitySensorToken(s.producer, s.sensor), s);
assert b1 == b2;
if (s.subscriber != null) {
boolean b3 =
LanguageUtils.removeFromMapOfCollections(subscriptionsBySubscriber, s.subscriber, s);
assert b3 == b2;
}
// TODO Requires code review: why did we previously do exactly same check twice in a row (with
// no synchronization in between)?
if ((subscriptionsBySubscriber.size() == 0
|| !groovyTruth(subscriptionsBySubscriber.get(s.subscriber)))
&& !s.subscriberExecutionManagerTagSupplied
&& s.subscriberExecutionManagerTag != null) {
// if subscriber has gone away forget about his task; but check in synch block to ensure
// setTaskPreprocessor call above will win in any race
if ((subscriptionsBySubscriber.size() == 0
|| !groovyTruth(subscriptionsBySubscriber.get(s.subscriber))))
((BasicExecutionManager) em).clearTaskPreprocessorForTag(s.subscriberExecutionManagerTag);
}
// FIXME ALEX - this seems wrong
((BasicExecutionManager) em)
.setTaskSchedulerForTag(s.subscriberExecutionManagerTag, SingleThreadedScheduler.class);
return b1;
}
