/** @param args */
public static void main(String[] args) {
HashSet<Teacher> aaSet = new HashSet<Teacher>();
Teacher aaTeacher = new Teacher("baicai", "07073120");
Teacher bbTeacher = new Teacher("baicai", "07073120");
Teacher ccTeacher = new Teacher("qingcai", "07073121");
Teacher ddTeacher = new Teacher("xigua", "07073122");
aaSet.add(aaTeacher);
aaSet.add(bbTeacher);
aaSet.add(ccTeacher);
aaSet.add(ddTeacher);
System.out.println(
"aaTeacher_"
+ aaTeacher.hashCode()
+ ".equals(bbTeacher_"
+ bbTeacher.hashCode()
+ ") = "
+ aaTeacher.equals(bbTeacher));
/** 由于重写了teacher里面的hashcode()方法，所以这边判断的时候，相同元素的hashcode就是一样的了， 就不会出现Taa的那个人问题了 */
System.out.println("对象的内容" + "\t\t" + "对象的散列码");
for (Teacher teacher : aaSet) {
System.out.println(teacher.toString() + "\t\t" + teacher.hashCode());
}
}
