/**
* Combine an older schedule (A) and a newer one (B) into a better schedule (C). 1. If a line is
* in B but not in A, add it to C, if a line is in both A and B, add B's version to C, If a line
* is only in A, still add it to C.
*
* @param oldSchedule
* @param newSched
* @return schedule built
*/
public Schedule mergeSchedule(Schedule oldSched, Schedule newSched) {
// first insert each line in new sched to the output while consulting the old sched
Schedule sched = new TrainSchedule("merged");
// first merge the station and areas
for (Station st1 : oldSched.getStations()) {
try {
sched.addStation(st1);
} catch (DuplicateStationException e) {
}
}
for (Station st2 : newSched.getStations()) {
try {
sched.addStation(st2);
} catch (DuplicateStationException e) {
}
}
try {
for (Line newLine : newSched.getLines()) {
sched.addLine(newLine);
}
// add all OLD lines back except ones already in the final result
for (Line oldLine : oldSched.getLines()) {
sched.addLine(oldLine);
}
} catch (Exception e) {
e.printStackTrace();
}
return sched;
}
public void diffLines(
Schedule sched1, Schedule sched2, List<String> onlyOneHas, List<String> onlyTwoHas) {
assert (onlyOneHas.size() == 0);
assert (onlyTwoHas.size() == 0);
for (Line line : sched1.getLines()) {
// if a line is in one but not in two
Line line2 = sched2.getLineEquivalentTo(line);
if (line2 == null) {
onlyOneHas.add(line.getFullNumber());
}
}
for (Line line : sched2.getLines()) {
// if a line is in one but not in two
Line line2 = sched1.getLineEquivalentTo(line);
if (line2 == null) {
onlyTwoHas.add(line.getFullNumber());
}
}
}