/*
* Scan the INList for all dirty INs. Arrange them in level sorted
* map for level ordered flushing.
*/
private SortedMap selectDirtyINs(boolean flushAll, boolean flushExtraLevel)
throws DatabaseException {
SortedMap newDirtyMap = new TreeMap();
INList inMemINs = envImpl.getInMemoryINs();
inMemINs.latchMajor();
/*
* Opportunistically recalculate the environment wide memory
* count. Incurs no extra cost because we're walking the IN
* list anyway. Not the best in terms of encapsulation as
* prefereably all memory calculations are done in
* MemoryBudget, but done this way to avoid any extra
* latching.
*/
long totalSize = 0;
MemoryBudget mb = envImpl.getMemoryBudget();
try {
Iterator iter = inMemINs.iterator();
while (iter.hasNext()) {
IN in = (IN) iter.next();
in.latch();
totalSize = mb.accumulateNewUsage(in, totalSize);
boolean isDirty = in.getDirty();
in.releaseLatch();
if (isDirty) {
Integer level = new Integer(in.getLevel());
Set dirtySet;
if (newDirtyMap.containsKey(level)) {
dirtySet = (Set) newDirtyMap.get(level);
} else {
dirtySet = new HashSet();
newDirtyMap.put(level, dirtySet);
}
dirtySet.add(in);
}
}
// Later release: refresh env count.
// mb.refreshCacheMemoryUsage(totalSize);
/*
* If we're flushing all for cleaning, we must flush to
* the point that there are no nodes with LSNs in the
* cleaned files. We could figure this out by perusing
* every node to see what children it has, but that's so
* expensive that instead we'll flush to the root.
*/
if (newDirtyMap.size() > 0) {
if (flushAll) {
highestFlushLevel = envImpl.getDbMapTree().getHighestLevel();
} else {
highestFlushLevel = ((Integer) newDirtyMap.lastKey()).intValue();
if (flushExtraLevel) {
highestFlushLevel += 1;
}
}
}
} finally {
inMemINs.releaseMajorLatchIfHeld();
}
return newDirtyMap;
}