Пример #1
0
 @Subroutine(value = "format")
 public static LispString format(LispString formatString, @Optional LispObject... objects) {
   checkFormatCharacters(formatString.getData());
   try {
     Object[] data = new Object[objects.length];
     for (int i = 0; i != objects.length; i++) {
       LispObject object = objects[i];
       data[i] =
           object instanceof LispNumber
               ? ((LispNumber) object).getData()
               : (object instanceof LispString
                   ? ((LispString) object).getData()
                   : object.toString());
     }
     return new LispString(String.format(formatString.getData(), data));
   } catch (MissingFormatArgumentException e1) {
     throw new LispException(JelispBundle.message("few.args.for.format.string"));
   } catch (UnknownFormatConversionException e2) {
     char c = e2.getMessage().charAt(e2.getMessage().length() - 2);
     if (c < 'A') throw new LispException(JelispBundle.message("unexpected.format.string.end"));
     throw new InvalidFormatOperationException(c);
   } catch (IllegalFormatConversionException e3) {
     throw new LispException(JelispBundle.message("format.arg.types.mismatch"));
   }
 }
Пример #2
0
 @Subroutine("substring-no-properties")
 public static LispString substringNoProperties(
     LispString string, @Optional LispObject from, LispObject to) {
   int length = string.size();
   int start = Predicate.isNil(from) ? 0 : processBound(getInt(from), length);
   int end = Predicate.isNil(to) ? length : processBound(getInt(to), length);
   try {
     return string.substring(start, end, false);
   } catch (IndexOutOfBoundsException e) {
     throw new ArgumentOutOfRange(string, start, end);
   }
 }
Пример #3
0
 @Subroutine(value = "string-match")
 public static LispObject stringMatch(
     Environment environment, LispString regexp, LispString string, @Optional LispInteger start) {
   int from = 0;
   if (start != null) {
     from = start.getData();
     if (from < 0 || from >= string.size())
       throw new ArgumentOutOfRange(string.toString(), start.toString());
   }
   LispSymbol s = environment.find("case-fold-search");
   int r =
       string.match(
           environment, regexp, from, (s != null && !s.getValue().equals(LispSymbol.ourNil)));
   if (r == -1) return LispSymbol.ourNil;
   return new LispInteger(r);
 }
Пример #4
0
 @Subroutine("read-from-string")
 public static LispList readFromString(
     LispString string,
     @Optional @Nullable LispObject start,
     @Optional @Nullable LispObject finish) {
   int begin = getInt(start, 0);
   int end = getInt(finish, string.size());
   try {
     String code = string.getData().substring(begin, end);
     ForwardParser forwardParser = new ForwardParser();
     LispObject read = Core.thisOrNil(forwardParser.parseLine(code));
     return LispList.cons(read, new LispInteger(begin + forwardParser.getCurrentIndex()));
   } catch (StringIndexOutOfBoundsException e) {
     throw new ArgumentOutOfRange(string, begin, end);
   }
 }
Пример #5
0
 @Subroutine("message")
 public static LispString message(@Optional LispObject... args) {
   if (args.length == 0) throw new WrongNumberOfArgumentsException("message", 0);
   LispObject formatObj = args[0];
   if (formatObj instanceof LispString) {
     LispObject[] a = new LispObject[args.length - 1];
     System.arraycopy(args, 1, a, 0, args.length - 1);
     myCurrentMessage = format((LispString) formatObj, a);
   } else if (formatObj.equals(LispSymbol.ourNil)) {
     myCurrentMessage = new LispString(LispSymbol.ourNil.toString());
   } else {
     throw new WrongTypeArgumentException("stringp", formatObj);
   }
   GlobalEnvironment.echo(myCurrentMessage.getData(), GlobalEnvironment.MessageType.OUTPUT);
   return myCurrentMessage;
 }
Пример #6
0
 @Subroutine("string-to-char")
 public static LispInteger stringToChar(LispString string) {
   return new LispInteger(string.getFirstCharacter());
 }
Пример #7
0
 @Subroutine("regexp-quote")
 public static LispString regexpQuote(LispString target) {
   return target.getExactRegexp();
 }
Пример #8
0
 @Subroutine("string-to-number")
 public static LispNumber stringToNumber(LispString string, @Optional LispObject baseObject) {
   int base = getInt(baseObject, 10);
   return string.toNumber(base);
 }